4(x-2)+x+1=2x-3+3(x-4)

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Solution for 4(x-2)+x+1=2x-3+3(x-4) equation: 



4(x-2)+x+1=2x-3+3(x-4)

We move all terms to the left:

4(x-2)+x+1-(2x-3+3(x-4))=0

We add all the numbers together, and all the variables

x+4(x-2)-(2x-3+3(x-4))+1=0

We multiply parentheses

x+4x-(2x-3+3(x-4))-8+1=0



We calculate terms in parentheses: -(2x-3+3(x-4)), so:

2x-3+3(x-4)

determiningTheFunctionDomain
2x+3(x-4)-3

We multiply parentheses

2x+3x-12-3

We add all the numbers together, and all the variables

5x-15

Back to the equation:

-(5x-15)



We add all the numbers together, and all the variables

5x-(5x-15)-7=0

We get rid of parentheses

5x-5x+15-7=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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