4(x-2)+x=3(x+4)

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Solution for 4(x-2)+x=3(x+4) equation: 



4(x-2)+x=3(x+4)

We move all terms to the left:

4(x-2)+x-(3(x+4))=0

We add all the numbers together, and all the variables

x+4(x-2)-(3(x+4))=0

We multiply parentheses

x+4x-(3(x+4))-8=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

5x-(3x+12)-8=0

We get rid of parentheses

5x-3x-12-8=0

We add all the numbers together, and all the variables

2x-20=0

We move all terms containing x to the left, all other terms to the right

2x=20

x=20/2

x=10

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