4(x-2)-(x+3)=x-1

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Solution for 4(x-2)-(x+3)=x-1 equation: 



4(x-2)-(x+3)=x-1

We move all terms to the left:

4(x-2)-(x+3)-(x-1)=0

We multiply parentheses

4x-(x+3)-(x-1)-8=0

We get rid of parentheses

4x-x-x-3+1-8=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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