4(x-2)-12=3(x-4)-12

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Solution for 4(x-2)-12=3(x-4)-12 equation: 



4(x-2)-12=3(x-4)-12

We move all terms to the left:

4(x-2)-12-(3(x-4)-12)=0

We multiply parentheses

4x-(3(x-4)-12)-8-12=0



We calculate terms in parentheses: -(3(x-4)-12), so:

3(x-4)-12

We multiply parentheses

3x-12-12

We add all the numbers together, and all the variables

3x-24

Back to the equation:

-(3x-24)



We add all the numbers together, and all the variables

4x-(3x-24)-20=0

We get rid of parentheses

4x-3x+24-20=0

We add all the numbers together, and all the variables

x+4=0

We move all terms containing x to the left, all other terms to the right

x=-4

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