4(x-2)-1=3(2+x)

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Solution for 4(x-2)-1=3(2+x) equation: 



4(x-2)-1=3(2+x)

We move all terms to the left:

4(x-2)-1-(3(2+x))=0

We add all the numbers together, and all the variables

4(x-2)-(3(x+2))-1=0

We multiply parentheses

4x-(3(x+2))-8-1=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

4x-(3x+6)-9=0

We get rid of parentheses

4x-3x-6-9=0

We add all the numbers together, and all the variables

x-15=0

We move all terms containing x to the left, all other terms to the right

x=15

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