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4(x-2)-2=3x-(x-2)
We move all terms to the left:
4(x-2)-2-(3x-(x-2))=0
We multiply parentheses
4x-(3x-(x-2))-8-2=0
We calculate terms in parentheses: -(3x-(x-2)), so:We add all the numbers together, and all the variables
3x-(x-2)
We get rid of parentheses
3x-x+2
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
4x-(2x+2)-10=0
We get rid of parentheses
4x-2x-2-10=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6
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