4(x-2)-3(3-x)=6x+6-3+3x

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Solution for 4(x-2)-3(3-x)=6x+6-3+3x equation: 



4(x-2)-3(3-x)=6x+6-3+3x

We move all terms to the left:

4(x-2)-3(3-x)-(6x+6-3+3x)=0

We add all the numbers together, and all the variables

4(x-2)-3(-1x+3)-(9x+3)=0

We multiply parentheses

4x+3x-(9x+3)-8-9=0

We get rid of parentheses

4x+3x-9x-3-8-9=0

We add all the numbers together, and all the variables

-2x-20=0

We move all terms containing x to the left, all other terms to the right

-2x=20

x=20/-2

x=-10

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