4(x-2)-3(x+1)=2(x+2)

Solution for 4(x-2)-3(x+1)=2(x+2) equation:

4(x-2)-3(x+1)=2(x+2)

We move all terms to the left:

4(x-2)-3(x+1)-(2(x+2))=0

We multiply parentheses

4x-3x-(2(x+2))-8-3=0


We calculate terms in parentheses: -(2(x+2)), so:

2(x+2)

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)


We add all the numbers together, and all the variables

x-(2x+4)-11=0

We get rid of parentheses

x-2x-4-11=0

We add all the numbers together, and all the variables

-1x-15=0

We move all terms containing x to the left, all other terms to the right

-x=15

x=15/-1

x=-15