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4(x-2)-3(x+2)=-7
We move all terms to the left:
4(x-2)-3(x+2)-(-7)=0
We add all the numbers together, and all the variables
4(x-2)-3(x+2)+7=0
We multiply parentheses
4x-3x-8-6+7=0
We add all the numbers together, and all the variables
x-7=0
We move all terms containing x to the left, all other terms to the right
x=7
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