4(x-2)-3=5(3-x)+1

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Solution for 4(x-2)-3=5(3-x)+1 equation: 



4(x-2)-3=5(3-x)+1

We move all terms to the left:

4(x-2)-3-(5(3-x)+1)=0

We add all the numbers together, and all the variables

4(x-2)-(5(-1x+3)+1)-3=0

We multiply parentheses

4x-(5(-1x+3)+1)-8-3=0



We calculate terms in parentheses: -(5(-1x+3)+1), so:

5(-1x+3)+1

We multiply parentheses

-5x+15+1

We add all the numbers together, and all the variables

-5x+16

Back to the equation:

-(-5x+16)



We add all the numbers together, and all the variables

4x-(-5x+16)-11=0

We get rid of parentheses

4x+5x-16-11=0

We add all the numbers together, and all the variables

9x-27=0

We move all terms containing x to the left, all other terms to the right

9x=27

x=27/9

x=3

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