4(x-2)-3x+5(6x-4)=15x-6(6+2x)+22

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Solution for 4(x-2)-3x+5(6x-4)=15x-6(6+2x)+22 equation: 



4(x-2)-3x+5(6x-4)=15x-6(6+2x)+22

We move all terms to the left:

4(x-2)-3x+5(6x-4)-(15x-6(6+2x)+22)=0

We add all the numbers together, and all the variables

4(x-2)-3x+5(6x-4)-(15x-6(2x+6)+22)=0

We add all the numbers together, and all the variables

-3x+4(x-2)+5(6x-4)-(15x-6(2x+6)+22)=0

We multiply parentheses

-3x+4x+30x-(15x-6(2x+6)+22)-8-20=0



We calculate terms in parentheses: -(15x-6(2x+6)+22), so:

15x-6(2x+6)+22

We multiply parentheses

15x-12x-36+22

We add all the numbers together, and all the variables

3x-14

Back to the equation:

-(3x-14)



We add all the numbers together, and all the variables

31x-(3x-14)-28=0

We get rid of parentheses

31x-3x+14-28=0

We add all the numbers together, and all the variables

28x-14=0

We move all terms containing x to the left, all other terms to the right

28x=14

x=14/28

x=1/2

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