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4(x-2)-4=2x+2(x-2)
We move all terms to the left:
4(x-2)-4-(2x+2(x-2))=0
We multiply parentheses
4x-(2x+2(x-2))-8-4=0
We calculate terms in parentheses: -(2x+2(x-2)), so:We add all the numbers together, and all the variables
2x+2(x-2)
We multiply parentheses
2x+2x-4
We add all the numbers together, and all the variables
4x-4
Back to the equation:
-(4x-4)
4x-(4x-4)-12=0
We get rid of parentheses
4x-4x+4-12=0
We add all the numbers together, and all the variables
-8!=0
There is no solution for this equation
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