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4(x-2)-5(2x-3)=8(x+1)-3(2x+3)
We move all terms to the left:
4(x-2)-5(2x-3)-(8(x+1)-3(2x+3))=0
We multiply parentheses
4x-10x-(8(x+1)-3(2x+3))-8+15=0
We calculate terms in parentheses: -(8(x+1)-3(2x+3)), so:We add all the numbers together, and all the variables
8(x+1)-3(2x+3)
We multiply parentheses
8x-6x+8-9
We add all the numbers together, and all the variables
2x-1
Back to the equation:
-(2x-1)
-6x-(2x-1)+7=0
We get rid of parentheses
-6x-2x+1+7=0
We add all the numbers together, and all the variables
-8x+8=0
We move all terms containing x to the left, all other terms to the right
-8x=-8
x=-8/-8
x=1
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