4(x-2)-5(2x-6)=8(x+1)-3(2+3)

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Solution for 4(x-2)-5(2x-6)=8(x+1)-3(2+3) equation: 



4(x-2)-5(2x-6)=8(x+1)-3(2+3)

We move all terms to the left:

4(x-2)-5(2x-6)-(8(x+1)-3(2+3))=0

We add all the numbers together, and all the variables

4(x-2)-5(2x-6)-(8(x+1)-35)=0

We multiply parentheses

4x-10x-(8(x+1)-35)-8+30=0



We calculate terms in parentheses: -(8(x+1)-35), so:

8(x+1)-35

We multiply parentheses

8x+8-35

We add all the numbers together, and all the variables

8x-27

Back to the equation:

-(8x-27)



We add all the numbers together, and all the variables

-6x-(8x-27)+22=0

We get rid of parentheses

-6x-8x+27+22=0

We add all the numbers together, and all the variables

-14x+49=0

We move all terms containing x to the left, all other terms to the right

-14x=-49

x=-49/-14

x=3+1/2

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