4(x-2)-5(x+2)=7(3x-15+29)

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Solution for 4(x-2)-5(x+2)=7(3x-15+29) equation: 



4(x-2)-5(x+2)=7(3x-15+29)

We move all terms to the left:

4(x-2)-5(x+2)-(7(3x-15+29))=0

We add all the numbers together, and all the variables

4(x-2)-5(x+2)-(7(3x+14))=0

We multiply parentheses

4x-5x-(7(3x+14))-8-10=0



We calculate terms in parentheses: -(7(3x+14)), so:

7(3x+14)

We multiply parentheses

21x+98

Back to the equation:

-(21x+98)



We add all the numbers together, and all the variables

-1x-(21x+98)-18=0

We get rid of parentheses

-1x-21x-98-18=0

We add all the numbers together, and all the variables

-22x-116=0

We move all terms containing x to the left, all other terms to the right

-22x=116

x=116/-22

x=-5+3/11

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