4(x-2)-7=4x-(3x-1)

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Solution for 4(x-2)-7=4x-(3x-1) equation:



4(x-2)-7=4x-(3x-1)
We move all terms to the left:
4(x-2)-7-(4x-(3x-1))=0
We multiply parentheses
4x-(4x-(3x-1))-8-7=0
We calculate terms in parentheses: -(4x-(3x-1)), so:
4x-(3x-1)
We get rid of parentheses
4x-3x+1
We add all the numbers together, and all the variables
x+1
Back to the equation:
-(x+1)
We add all the numbers together, and all the variables
4x-(x+1)-15=0
We get rid of parentheses
4x-x-1-15=0
We add all the numbers together, and all the variables
3x-16=0
We move all terms containing x to the left, all other terms to the right
3x=16
x=16/3
x=5+1/3

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