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4(x-2)-x-5x-2+3(2-x)=5x-2+2(2x-1)-3+11
We move all terms to the left:
4(x-2)-x-5x-2+3(2-x)-(5x-2+2(2x-1)-3+11)=0
We add all the numbers together, and all the variables
4(x-2)-x-5x+3(-1x+2)-(5x-2+2(2x-1)-3+11)-2=0
We add all the numbers together, and all the variables
-6x+4(x-2)+3(-1x+2)-(5x-2+2(2x-1)-3+11)-2=0
We multiply parentheses
-6x+4x-3x-(5x-2+2(2x-1)-3+11)-8+6-2=0
We calculate terms in parentheses: -(5x-2+2(2x-1)-3+11), so:We add all the numbers together, and all the variables
5x-2+2(2x-1)-3+11
determiningTheFunctionDomain 5x+2(2x-1)-2-3+11
We add all the numbers together, and all the variables
5x+2(2x-1)+6
We multiply parentheses
5x+4x-2+6
We add all the numbers together, and all the variables
9x+4
Back to the equation:
-(9x+4)
-5x-(9x+4)-4=0
We get rid of parentheses
-5x-9x-4-4=0
We add all the numbers together, and all the variables
-14x-8=0
We move all terms containing x to the left, all other terms to the right
-14x=8
x=8/-14
x=-4/7
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