4(x-2)/6=4(x+1)/12

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Solution for 4(x-2)/6=4(x+1)/12 equation: 



4(x-2)/6=4(x+1)/12

We move all terms to the left:

4(x-2)/6-(4(x+1)/12)=0

We calculate fractions


4x/()+(-(4(x+1)*6)/()=0



We calculate terms in parentheses: +(-(4(x+1)*6)/(), so:

-(4(x+1)*6)/(

We multiply all the terms by the denominator


-(4(x+1)*6)



We calculate terms in parentheses: -(4(x+1)*6), so:

4(x+1)*6

We multiply parentheses

24x+24

Back to the equation:

-(24x+24)



We get rid of parentheses

-24x-24

Back to the equation:

+(-24x-24)



We get rid of parentheses

4x/()-24x-24=0

We multiply all the terms by the denominator


4x-24x*()-24*()=0

We add all the numbers together, and all the variables

4x-24x*()=0

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