4(x-2)/8=2(x+3)/9

Solution for 4(x-2)/8=2(x+3)/9 equation:

4(x-2)/8=2(x+3)/9

We move all terms to the left:

4(x-2)/8-(2(x+3)/9)=0

We calculate fractions


4x/()+(-(2(x+3)*8)/()=0


We calculate terms in parentheses: +(-(2(x+3)*8)/(), so:

-(2(x+3)*8)/(

We multiply all the terms by the denominator


-(2(x+3)*8)


We calculate terms in parentheses: -(2(x+3)*8), so:

2(x+3)*8

We multiply parentheses

16x+48

Back to the equation:

-(16x+48)


We get rid of parentheses

-16x-48

Back to the equation:

+(-16x-48)


We get rid of parentheses

4x/()-16x-48=0

We multiply all the terms by the denominator


4x-16x*()-48*()=0

We add all the numbers together, and all the variables

4x-16x*()=0