4(x-2)=2(x+3)+10

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Solution for 4(x-2)=2(x+3)+10 equation: 



4(x-2)=2(x+3)+10

We move all terms to the left:

4(x-2)-(2(x+3)+10)=0

We multiply parentheses

4x-(2(x+3)+10)-8=0



We calculate terms in parentheses: -(2(x+3)+10), so:

2(x+3)+10

We multiply parentheses

2x+6+10

We add all the numbers together, and all the variables

2x+16

Back to the equation:

-(2x+16)



We get rid of parentheses

4x-2x-16-8=0

We add all the numbers together, and all the variables

2x-24=0

We move all terms containing x to the left, all other terms to the right

2x=24

x=24/2

x=12

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