4(x-2)=3(x+1)+4

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Solution for 4(x-2)=3(x+1)+4 equation: 



4(x-2)=3(x+1)+4

We move all terms to the left:

4(x-2)-(3(x+1)+4)=0

We multiply parentheses

4x-(3(x+1)+4)-8=0



We calculate terms in parentheses: -(3(x+1)+4), so:

3(x+1)+4

We multiply parentheses

3x+3+4

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We get rid of parentheses

4x-3x-7-8=0

We add all the numbers together, and all the variables

x-15=0

We move all terms containing x to the left, all other terms to the right

x=15

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