4(x-2)=3(x+1)-6

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Solution for 4(x-2)=3(x+1)-6 equation: 



4(x-2)=3(x+1)-6

We move all terms to the left:

4(x-2)-(3(x+1)-6)=0

We multiply parentheses

4x-(3(x+1)-6)-8=0



We calculate terms in parentheses: -(3(x+1)-6), so:

3(x+1)-6

We multiply parentheses

3x+3-6

We add all the numbers together, and all the variables

3x-3

Back to the equation:

-(3x-3)



We get rid of parentheses

4x-3x+3-8=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

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