4(x-2)=3(x-1)+x-5

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Solution for 4(x-2)=3(x-1)+x-5 equation: 



4(x-2)=3(x-1)+x-5

We move all terms to the left:

4(x-2)-(3(x-1)+x-5)=0

We multiply parentheses

4x-(3(x-1)+x-5)-8=0



We calculate terms in parentheses: -(3(x-1)+x-5), so:

3(x-1)+x-5

We add all the numbers together, and all the variables

x+3(x-1)-5

We multiply parentheses

x+3x-3-5

We add all the numbers together, and all the variables

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

4x-4x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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