4(x-2)=5(x+3)+6

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Solution for 4(x-2)=5(x+3)+6 equation: 



4(x-2)=5(x+3)+6

We move all terms to the left:

4(x-2)-(5(x+3)+6)=0

We multiply parentheses

4x-(5(x+3)+6)-8=0



We calculate terms in parentheses: -(5(x+3)+6), so:

5(x+3)+6

We multiply parentheses

5x+15+6

We add all the numbers together, and all the variables

5x+21

Back to the equation:

-(5x+21)



We get rid of parentheses

4x-5x-21-8=0

We add all the numbers together, and all the variables

-1x-29=0

We move all terms containing x to the left, all other terms to the right

-x=29

x=29/-1

x=-29

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