4(x-2)=6(x+3)-2

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Solution for 4(x-2)=6(x+3)-2 equation: 



4(x-2)=6(x+3)-2

We move all terms to the left:

4(x-2)-(6(x+3)-2)=0

We multiply parentheses

4x-(6(x+3)-2)-8=0



We calculate terms in parentheses: -(6(x+3)-2), so:

6(x+3)-2

We multiply parentheses

6x+18-2

We add all the numbers together, and all the variables

6x+16

Back to the equation:

-(6x+16)



We get rid of parentheses

4x-6x-16-8=0

We add all the numbers together, and all the variables

-2x-24=0

We move all terms containing x to the left, all other terms to the right

-2x=24

x=24/-2

x=-12

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