4(x-2)=x+4+3(x-4)

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Solution for 4(x-2)=x+4+3(x-4) equation:



4(x-2)=x+4+3(x-4)
We move all terms to the left:
4(x-2)-(x+4+3(x-4))=0
We multiply parentheses
4x-(x+4+3(x-4))-8=0
We calculate terms in parentheses: -(x+4+3(x-4)), so:
x+4+3(x-4)
determiningTheFunctionDomain x+3(x-4)+4
We multiply parentheses
x+3x-12+4
We add all the numbers together, and all the variables
4x-8
Back to the equation:
-(4x-8)
We get rid of parentheses
4x-4x+8-8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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