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4(x-3)(6x+1)=0
We multiply parentheses ..
4(+6x^2+x-18x-3)=0
We multiply parentheses
24x^2+4x-72x-12=0
We add all the numbers together, and all the variables
24x^2-68x-12=0
a = 24; b = -68; c = -12;
Δ = b2-4ac
Δ = -682-4·24·(-12)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-76}{2*24}=\frac{-8}{48} =-1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+76}{2*24}=\frac{144}{48} =3 $
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