4(x-3)+(x-5)=0

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Solution for 4(x-3)+(x-5)=0 equation: 



4(x-3)+(x-5)=0

We multiply parentheses

4x+(x-5)-12=0

We get rid of parentheses

4x+x-5-12=0

We add all the numbers together, and all the variables

5x-17=0

We move all terms containing x to the left, all other terms to the right

5x=17

x=17/5

x=3+2/5

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