4(x-3)+10-x+2+2x=1-x-(6-7x)

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Solution for 4(x-3)+10-x+2+2x=1-x-(6-7x) equation: 



4(x-3)+10-x+2+2x=1-x-(6-7x)

We move all terms to the left:

4(x-3)+10-x+2+2x-(1-x-(6-7x))=0

We add all the numbers together, and all the variables

4(x-3)-x+2x-(1-x-(-7x+6))+10+2=0

We add all the numbers together, and all the variables

x+4(x-3)-(1-x-(-7x+6))+12=0

We multiply parentheses

x+4x-(1-x-(-7x+6))-12+12=0



We calculate terms in parentheses: -(1-x-(-7x+6)), so:

1-x-(-7x+6)

determiningTheFunctionDomain
-x-(-7x+6)+1

We add all the numbers together, and all the variables

-1x-(-7x+6)+1

We get rid of parentheses

-1x+7x-6+1

We add all the numbers together, and all the variables

6x-5

Back to the equation:

-(6x-5)



We add all the numbers together, and all the variables

5x-(6x-5)=0

We get rid of parentheses

5x-6x+5=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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