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4(x-3)+14=5x-(x-2)
We move all terms to the left:
4(x-3)+14-(5x-(x-2))=0
We multiply parentheses
4x-(5x-(x-2))-12+14=0
We calculate terms in parentheses: -(5x-(x-2)), so:We add all the numbers together, and all the variables
5x-(x-2)
We get rid of parentheses
5x-x+2
We add all the numbers together, and all the variables
4x+2
Back to the equation:
-(4x+2)
4x-(4x+2)+2=0
We get rid of parentheses
4x-4x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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