4(x-3)+19=8(2x+3)+7

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Solution for 4(x-3)+19=8(2x+3)+7 equation:



4(x-3)+19=8(2x+3)+7
We move all terms to the left:
4(x-3)+19-(8(2x+3)+7)=0
We multiply parentheses
4x-(8(2x+3)+7)-12+19=0
We calculate terms in parentheses: -(8(2x+3)+7), so:
8(2x+3)+7
We multiply parentheses
16x+24+7
We add all the numbers together, and all the variables
16x+31
Back to the equation:
-(16x+31)
We add all the numbers together, and all the variables
4x-(16x+31)+7=0
We get rid of parentheses
4x-16x-31+7=0
We add all the numbers together, and all the variables
-12x-24=0
We move all terms containing x to the left, all other terms to the right
-12x=24
x=24/-12
x=-2

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