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4(x-3)+1=12-3(1-2x)
We move all terms to the left:
4(x-3)+1-(12-3(1-2x))=0
We add all the numbers together, and all the variables
4(x-3)-(12-3(-2x+1))+1=0
We multiply parentheses
4x-(12-3(-2x+1))-12+1=0
We calculate terms in parentheses: -(12-3(-2x+1)), so:We add all the numbers together, and all the variables
12-3(-2x+1)
determiningTheFunctionDomain -3(-2x+1)+12
We multiply parentheses
6x-3+12
We add all the numbers together, and all the variables
6x+9
Back to the equation:
-(6x+9)
4x-(6x+9)-11=0
We get rid of parentheses
4x-6x-9-11=0
We add all the numbers together, and all the variables
-2x-20=0
We move all terms containing x to the left, all other terms to the right
-2x=20
x=20/-2
x=-10
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