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4(x-3)+1=4(x-3)
We move all terms to the left:
4(x-3)+1-(4(x-3))=0
We multiply parentheses
4x-(4(x-3))-12+1=0
We calculate terms in parentheses: -(4(x-3)), so:We add all the numbers together, and all the variables
4(x-3)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
4x-(4x-12)-11=0
We get rid of parentheses
4x-4x+12-11=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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