4(x-3)+1=6(x-2)-5

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Solution for 4(x-3)+1=6(x-2)-5 equation:


Simplifying
4(x + -3) + 1 = 6(x + -2) + -5

Reorder the terms:
4(-3 + x) + 1 = 6(x + -2) + -5
(-3 * 4 + x * 4) + 1 = 6(x + -2) + -5
(-12 + 4x) + 1 = 6(x + -2) + -5

Reorder the terms:
-12 + 1 + 4x = 6(x + -2) + -5

Combine like terms: -12 + 1 = -11
-11 + 4x = 6(x + -2) + -5

Reorder the terms:
-11 + 4x = 6(-2 + x) + -5
-11 + 4x = (-2 * 6 + x * 6) + -5
-11 + 4x = (-12 + 6x) + -5

Reorder the terms:
-11 + 4x = -12 + -5 + 6x

Combine like terms: -12 + -5 = -17
-11 + 4x = -17 + 6x

Solving
-11 + 4x = -17 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
-11 + 4x + -6x = -17 + 6x + -6x

Combine like terms: 4x + -6x = -2x
-11 + -2x = -17 + 6x + -6x

Combine like terms: 6x + -6x = 0
-11 + -2x = -17 + 0
-11 + -2x = -17

Add '11' to each side of the equation.
-11 + 11 + -2x = -17 + 11

Combine like terms: -11 + 11 = 0
0 + -2x = -17 + 11
-2x = -17 + 11

Combine like terms: -17 + 11 = -6
-2x = -6

Divide each side by '-2'.
x = 3

Simplifying
x = 3

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