4(x-3)+2(x+3)=3(x-2)+2(x+2)

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Solution for 4(x-3)+2(x+3)=3(x-2)+2(x+2) equation:


4(x-3)+2(x+3)=3(x-2)+2(x+2)

We simplify the equation to the form, which is simple to understand
4(x-3)+2(x+3)=3(x-2)+2(x+2)

Reorder the terms in parentheses
+(+4x-12)+2*(x+3)=3*(x-2)+2*(x+2)

Remove unnecessary parentheses
+4x-12+2+*(+x+3+)=+3+*(+x-2+)+2+*(+x+2+)

Reorder the terms in parentheses
+4x-12+(+2x+6)=3*(x-2)+2*(x+2)

Remove unnecessary parentheses
+4x-12+2x+6=+3+*(+x-2+)+2+*(+x+2+)

Reorder the terms in parentheses
+4x-12+2x+6=+(+3x-6)+2*(x+2)

Remove unnecessary parentheses
+4x-12+2x+6=+3x-6+2+*(+x+2+)

Reorder the terms in parentheses
+4x-12+2x+6=+3x-6+(+2x+4)

Remove unnecessary parentheses
+4x-12+2x+6=+3x-6+2x+4

We move all terms containing x to the left and all other terms to the right.
+4x+2x-3x-2x=-6+4+12-6

We simplify left and right side of the equation.
+1x=+4

We divide both sides of the equation by 1 to get x.
x=4

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