4(x-3)+2(x-5)-5(2x-1)+3(x+2)=2

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Solution for 4(x-3)+2(x-5)-5(2x-1)+3(x+2)=2 equation:



4(x-3)+2(x-5)-5(2x-1)+3(x+2)=2
We move all terms to the left:
4(x-3)+2(x-5)-5(2x-1)+3(x+2)-(2)=0
We multiply parentheses
4x+2x-10x+3x-12-10+5+6-2=0
We add all the numbers together, and all the variables
-1x-13=0
We move all terms containing x to the left, all other terms to the right
-x=13
x=13/-1
x=-13

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