4(x-3)+2=4+6(x+2)

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Solution for 4(x-3)+2=4+6(x+2) equation: 



4(x-3)+2=4+6(x+2)

We move all terms to the left:

4(x-3)+2-(4+6(x+2))=0

We multiply parentheses

4x-(4+6(x+2))-12+2=0



We calculate terms in parentheses: -(4+6(x+2)), so:

4+6(x+2)

determiningTheFunctionDomain
6(x+2)+4

We multiply parentheses

6x+12+4

We add all the numbers together, and all the variables

6x+16

Back to the equation:

-(6x+16)



We add all the numbers together, and all the variables

4x-(6x+16)-10=0

We get rid of parentheses

4x-6x-16-10=0

We add all the numbers together, and all the variables

-2x-26=0

We move all terms containing x to the left, all other terms to the right

-2x=26

x=26/-2

x=-13

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