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4(x-3)+2=5(x-4)-9
We move all terms to the left:
4(x-3)+2-(5(x-4)-9)=0
We multiply parentheses
4x-(5(x-4)-9)-12+2=0
We calculate terms in parentheses: -(5(x-4)-9), so:We add all the numbers together, and all the variables
5(x-4)-9
We multiply parentheses
5x-20-9
We add all the numbers together, and all the variables
5x-29
Back to the equation:
-(5x-29)
4x-(5x-29)-10=0
We get rid of parentheses
4x-5x+29-10=0
We add all the numbers together, and all the variables
-1x+19=0
We move all terms containing x to the left, all other terms to the right
-x=-19
x=-19/-1
x=+19
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