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4(x-3)+3x=12(x-1)-5x
We move all terms to the left:
4(x-3)+3x-(12(x-1)-5x)=0
We add all the numbers together, and all the variables
3x+4(x-3)-(12(x-1)-5x)=0
We multiply parentheses
3x+4x-(12(x-1)-5x)-12=0
We calculate terms in parentheses: -(12(x-1)-5x), so:We add all the numbers together, and all the variables
12(x-1)-5x
We add all the numbers together, and all the variables
-5x+12(x-1)
We multiply parentheses
-5x+12x-12
We add all the numbers together, and all the variables
7x-12
Back to the equation:
-(7x-12)
7x-(7x-12)-12=0
We get rid of parentheses
7x-7x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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