4(x-3)+3x=2(3x-5)-(1-x)

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Solution for 4(x-3)+3x=2(3x-5)-(1-x) equation: 


Simplifying
4(x + -3) + 3x = 2(3x + -5) + -1(1 + -1x)

Reorder the terms:
4(-3 + x) + 3x = 2(3x + -5) + -1(1 + -1x)
(-3 * 4 + x * 4) + 3x = 2(3x + -5) + -1(1 + -1x)
(-12 + 4x) + 3x = 2(3x + -5) + -1(1 + -1x)

Combine like terms: 4x + 3x = 7x
-12 + 7x = 2(3x + -5) + -1(1 + -1x)

Reorder the terms:
-12 + 7x = 2(-5 + 3x) + -1(1 + -1x)
-12 + 7x = (-5 * 2 + 3x * 2) + -1(1 + -1x)
-12 + 7x = (-10 + 6x) + -1(1 + -1x)
-12 + 7x = -10 + 6x + (1 * -1 + -1x * -1)
-12 + 7x = -10 + 6x + (-1 + 1x)

Reorder the terms:
-12 + 7x = -10 + -1 + 6x + 1x

Combine like terms: -10 + -1 = -11
-12 + 7x = -11 + 6x + 1x

Combine like terms: 6x + 1x = 7x
-12 + 7x = -11 + 7x

Add '-7x' to each side of the equation.
-12 + 7x + -7x = -11 + 7x + -7x

Combine like terms: 7x + -7x = 0
-12 + 0 = -11 + 7x + -7x
-12 = -11 + 7x + -7x

Combine like terms: 7x + -7x = 0
-12 = -11 + 0
-12 = -11

Solving
-12 = -11

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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