4(x-3)+3x=3(x+2)+5

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Solution for 4(x-3)+3x=3(x+2)+5 equation: 



4(x-3)+3x=3(x+2)+5

We move all terms to the left:

4(x-3)+3x-(3(x+2)+5)=0

We add all the numbers together, and all the variables

3x+4(x-3)-(3(x+2)+5)=0

We multiply parentheses

3x+4x-(3(x+2)+5)-12=0



We calculate terms in parentheses: -(3(x+2)+5), so:

3(x+2)+5

We multiply parentheses

3x+6+5

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)



We add all the numbers together, and all the variables

7x-(3x+11)-12=0

We get rid of parentheses

7x-3x-11-12=0

We add all the numbers together, and all the variables

4x-23=0

We move all terms containing x to the left, all other terms to the right

4x=23

x=23/4

x=5+3/4

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