4(x-3)+40=64-3(x-2

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Solution for 4(x-3)+40=64-3(x-2 equation: 



4(x-3)+40=64-3(x-2

We move all terms to the left:

4(x-3)+40-(64-3(x-2)=0

We multiply parentheses

4x-(64-3(x-2)+40-12=0

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