4(x-3)+4=6x-3(x-4)

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Solution for 4(x-3)+4=6x-3(x-4) equation: 



4(x-3)+4=6x-3(x-4)

We move all terms to the left:

4(x-3)+4-(6x-3(x-4))=0

We multiply parentheses

4x-(6x-3(x-4))-12+4=0



We calculate terms in parentheses: -(6x-3(x-4)), so:

6x-3(x-4)

We multiply parentheses

6x-3x+12

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

4x-(3x+12)-8=0

We get rid of parentheses

4x-3x-12-8=0

We add all the numbers together, and all the variables

x-20=0

We move all terms containing x to the left, all other terms to the right

x=20

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