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4(x-3)+4=8(1/2x-1
We move all terms to the left:
4(x-3)+4-(8(1/2x-1)=0
Domain of the equation: 2x-1)+4!=0We multiply parentheses
x∈R
4x-(8(1/2x-1)+4-12=0
We multiply all the terms by the denominator
4x*2x-1)+4-12-(8(1=0
We add all the numbers together, and all the variables
4x*2x=0
Wy multiply elements
8x^2=0
a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{16}=0$
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