4(x-3)+5(x+4)=27

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Solution for 4(x-3)+5(x+4)=27 equation: 



4(x-3)+5(x+4)=27

We move all terms to the left:

4(x-3)+5(x+4)-(27)=0

We multiply parentheses

4x+5x-12+20-27=0

We add all the numbers together, and all the variables

9x-19=0

We move all terms containing x to the left, all other terms to the right

9x=19

x=19/9

x=2+1/9

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