4(x-3)+6(x-5)=-62

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Solution for 4(x-3)+6(x-5)=-62 equation: 



4(x-3)+6(x-5)=-62

We move all terms to the left:

4(x-3)+6(x-5)-(-62)=0

We add all the numbers together, and all the variables

4(x-3)+6(x-5)+62=0

We multiply parentheses

4x+6x-12-30+62=0

We add all the numbers together, and all the variables

10x+20=0

We move all terms containing x to the left, all other terms to the right

10x=-20

x=-20/10

x=-2

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