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4(x-3)+6=6x-2(4+x)
We move all terms to the left:
4(x-3)+6-(6x-2(4+x))=0
We add all the numbers together, and all the variables
4(x-3)-(6x-2(x+4))+6=0
We multiply parentheses
4x-(6x-2(x+4))-12+6=0
We calculate terms in parentheses: -(6x-2(x+4)), so:We add all the numbers together, and all the variables
6x-2(x+4)
We multiply parentheses
6x-2x-8
We add all the numbers together, and all the variables
4x-8
Back to the equation:
-(4x-8)
4x-(4x-8)-6=0
We get rid of parentheses
4x-4x+8-6=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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