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4(x-3)+7=6x-2(5+x)
We move all terms to the left:
4(x-3)+7-(6x-2(5+x))=0
We add all the numbers together, and all the variables
4(x-3)-(6x-2(x+5))+7=0
We multiply parentheses
4x-(6x-2(x+5))-12+7=0
We calculate terms in parentheses: -(6x-2(x+5)), so:We add all the numbers together, and all the variables
6x-2(x+5)
We multiply parentheses
6x-2x-10
We add all the numbers together, and all the variables
4x-10
Back to the equation:
-(4x-10)
4x-(4x-10)-5=0
We get rid of parentheses
4x-4x+10-5=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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