4(x-3)+7x=5x+6(x-2)

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Solution for 4(x-3)+7x=5x+6(x-2) equation: 



4(x-3)+7x=5x+6(x-2)

We move all terms to the left:

4(x-3)+7x-(5x+6(x-2))=0

We add all the numbers together, and all the variables

7x+4(x-3)-(5x+6(x-2))=0

We multiply parentheses

7x+4x-(5x+6(x-2))-12=0



We calculate terms in parentheses: -(5x+6(x-2)), so:

5x+6(x-2)

We multiply parentheses

5x+6x-12

We add all the numbers together, and all the variables

11x-12

Back to the equation:

-(11x-12)



We add all the numbers together, and all the variables

11x-(11x-12)-12=0

We get rid of parentheses

11x-11x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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