4(x-3)+8=6x-2(1+x)

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Solution for 4(x-3)+8=6x-2(1+x) equation: 



4(x-3)+8=6x-2(1+x)

We move all terms to the left:

4(x-3)+8-(6x-2(1+x))=0

We add all the numbers together, and all the variables

4(x-3)-(6x-2(x+1))+8=0

We multiply parentheses

4x-(6x-2(x+1))-12+8=0



We calculate terms in parentheses: -(6x-2(x+1)), so:

6x-2(x+1)

We multiply parentheses

6x-2x-2

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We add all the numbers together, and all the variables

4x-(4x-2)-4=0

We get rid of parentheses

4x-4x+2-4=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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